Answer

Each time through the loop we add a new term into the running sum and increment i in preparation for the next trip through the loop.

  while (i <= n) {
    sum = sum + 1/(2.0*i);
    i = i + 1;
  }

Notice the use of the floating-point constant 2.0 instead of the integer constant 2 in the denominator. We do this so that 2.0*n will also be a floating-point number, which means that the division will produce a floating-point result.

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Joseph L. Zachary
Hamlet Project
Department of Computer Science
University of Utah